Property Address: 600 E Sanford St, LAKE ALFRED, FL, 33850-3126
Average square foot calculated using Size range provided by listing agent.
Description
The property you are inquiring about is located in Lake Alfred, FL in the East area of Polk County. This is just a gem in the easy-access area of Lake Alfred. Located on a corner lot of 100x141 with privacy fence, screened patio for entertaining around the pool. This beautiful 3 bedroom, 2 bathroom home, with open floorplan and durable tile throughout, nice fireplace in the gathering area, with new kitchen granite-topping, plus an additional flex room for lifestyle convenience, two-car garage, and a full-service house generator. Fabulous value in NO HOA! **Agents, please see MLS remarks.**